ME 365 Review 4

ME 365 Exam 1 Review

Dynamics • Laplace • Transfer Functions • State Space • Uncertainty


This article reorganizes engineering exam-style problems into a modern review guide for studying and concept review.

Multiple Choice Review

1. State Variable Block Diagram

Given the governing equations:

\[ \dot x_1=-4x_1-3x_2 \]
\[ \dot x_2=5x_1-x_2+u \]

Determine the constant \(c_2\).

\[ sX_2(s)=5X_1(s)-X_2(s)+U(s) \]
\[ c_2=-5 \]

2. Steady State Response

The total response is:

\[ y(t)= -8\cos(3t)+6\sin(3t) +10e^{-t}\cos(2t) -4e^{-t}\sin(2t) \]

The exponential terms decay with time, so the steady-state response is:

\[ y_{ss}(t)= -8\cos(3t)+6\sin(3t) \]

3. ADC Quantization Uncertainty

A 4-bit ADC with range 0–10 V has:

\[ 2^4=16 \text{ levels} \]
\[ Q=\frac{10-0}{16} = \frac{5}{8}V \]

Measurement uncertainty:

\[ u=\pm\frac{Q}{2} = \pm\frac{5}{16}V \]

4. Number of State Variables

The reduced transfer function becomes:

\[ \frac{Y(s)}{R(s)} = \frac{7s^2+39s+50} {s^3+14s^2+45s+50} \]

The denominator is third order.

3 state variables

5. State Space Matrix B

\[ B= \begin{bmatrix} 2 & 1 & 0\\ 0 & 0 & 3 \end{bmatrix} \]

The number of columns equals the number of inputs.

The system has 3 inputs.

6. Spring Tensile Force

The spring deformation is the relative displacement:

\[ x_1-x_2 \]
\[ T_s=k(x_1-x_2) \]

7. Kinematic Constraint Equation

Using geometry of the crank-slider mechanism:

\[ x_1=l_2\cos(\theta_2)-r_3\cos(\theta_3) \]

8. Block Diagram Transfer Function

Set:

\[ U_2(s)=0 \]
\[ Y(s)=A(s)(U_1(s)-B(s)U_1(s)) \]
\[ G(s)=A(s)(1-B(s)) \]

9. Confidence Interval Interpretation

A confidence interval means:

If the experiment is repeated many times, approximately 95% of the intervals will contain the true mean.

10. Bias Error

Measured average:

\[ \bar H=9.94mm \]

True value:

\[ H_{true}=10mm \]
\[ B_H\approx|9.94-10| = 0.06mm \]

Free Response Problems

11. Inverted Pendulum Transfer Function

\[ m\ddot y-\frac12 ml\ddot\theta=f \]
\[ \ddot y-\frac23 l\ddot\theta+g\theta=0 \]

Apply the Laplace transform:

\[ ms^2Y(s)-\frac12 mls^2\Theta(s)=F(s) \]
\[ s^2Y(s)-\frac23 ls^2\Theta(s)+g\Theta(s)=0 \]
\[ \frac{\Theta(s)}{F(s)} = \frac{1} {\frac16 mls^2-mg} \]

12. Candy Jar Confidence Interval

Nominal candy count:

\[ N=\frac{500}{0.50}=1000 \]

95% confidence interval:

\[ 1000\pm5 \]

13. Calibration Uncertainty

Best-fit calibration line:

\[ v=2.0084h-0.023 \]

Maximum nonlinearity occurs near:

\[ h=2cm \]
\[ |max nonlinearity| = |2.0084(2)-0.023-3.759| \]
\[ u_h\approx\pm0.12cm \]

14. Equation of Motion

Torsional spring:

\[ T_s=k_T\theta \]

Torsional damper:

\[ T_d=c_T(\dot\theta-\dot\phi) \]

Moment equation:

\[ -T_d-T_s=I\ddot\theta \]
\[ I\ddot\theta +c_T\dot\theta +k_T\theta = c_T\dot\phi \]

15. Laplace Total Response

\[ \ddot y+6\dot y+13y=26u_s(t) \]

Apply the Laplace transform:

\[ Y(s)= \frac{26} {s(s^2+6s+13)} \]

Partial fraction expansion:

\[ Y(s)= \frac2s -\frac{2(s+3)} {(s+3)^2+2^2} -\frac3 {(s+3)^2+2^2} \]
\[ y(t)= 2-e^{-3t} (2\cos(2t)+3\sin(2t)) \]
Exam Tips
  • Always define coordinates before deriving equations of motion.
  • Transfer functions use zero initial conditions.
  • Steady-state response excludes transient exponential terms.
  • Confidence intervals describe repeated experiments, not individual measurements.
  • Uncertainty propagation often uses partial derivatives.
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